10 poin Rectangle FGH) has coordinates F(-8,6),
is dilated by a scale factor of 3. Which shows
G(8, 6), H(8,-6), and 1(-8,-6). The rectange
the effect of the scale factor on rectangle
FGHJ to form rectangle F'G'HT?
(x + 3, y + 3)
© (x - 3, y - 3)
D (3x, 3y)

Part A From the choices provided, select all the questions that represent statistical questions. What was the temperature at 5:00 p.m. today in Boston? What was the temperature at 5:00 p.m. today in Boston? How many pieces of fruit were used to make Shawn’s smoothie today? How many pieces of fruit were used to make Shawn’s smoothie today? How many states are there? How many states are there? What types of food do students in your school bring for lunch each day? What types of food do students in your school bring for lunch each day? How many books did each student check out at the library last year? How many books did each student check out at the library last year? Question 2 Part B Of the statistical questions you selected, which are categorical? Explain.

answer: its c because when it has a magnet next to it it will move away from the mixture. hope this

step-by-step explanation:

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.