I summed my square-side seven times and the area eleven times so that it was 6;15. What is the length of the side of my square

1 ÷ 2

Step-by-step explanation:

Given that

The square side is seven times

And, the area is eleven times

So it is 6;15

We need to find out the length of the side of the square

So,

let us assume the side of square be S

Now the area  is S^2

Now  

11S^2 + 7S = 6.15

11S^2 + 7S - 6.15=0    

Now the quadratic equation should be followed  

=  (-b+- √ (b^2-4ac)) ÷ 2a        

Here  a = 11,b = 7,c = -6.15

so

S = 0.4944, -1.1307

As we know that the side cant be negative so

Therefore

S = 0.4944 ≈ 0.5 = 1 ÷ 2

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x