The stopping distance, d, of an automobile varies directly to its speed, s, squared. A car required 75 feet to stop when it was 30 mph. What is the stopping distance if a car is traveling 50 mph.

your answer is the frist one

hop i

answer: b.36 feet

step-by-step explanation:

this is a direct variation proportion. y = kx

y is the total amount due, k is the constant of variation, and x is the number of texts sent.

plug in the 3.20 and the 16 to solve for the "k". this is the constant of proportionality. it is the value that will not change.

3.20 = k(16). solving you get $.20 per text.

the equation would then be y = .20x