A submarine travels 8.6 km due North from its base and then turns and travels due West for 11.4 km. How far away is the submarine from its base? Give your answer rounded to 1 DP.

The submarine is 14.28 kilometers away from its base.

Step-by-step explanation:

Given that a submarine travels 8.6 km due North from its base and then turns and travels due West for 11.4 km, to determine how far away is the submarine from its base the following calculation must be performed, applying the Pythagorean Theorem:

8.6 ^ 2 + 11.4 ^ 2 = X ^ 2

73.96 + 129.96 = X ^ 2

√203.92 = X

14.28 = X

Therefore, the submarine is 14.28 kilometers away from its base.

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true