Find the measure of arc CD in p​

9514 1404 393

  57°

Step-by-step explanation:

TD is a diameter, so arc TCD is 180°. Then arc CD is ...

  CD = arc TCD -arc TC

  CD = 180° -123°

  arc CD = 57°

Find the measure of arc CD in P.

Because Arc TC and Arc CD comprise the Arc TCD,

⇒ Arc TC + Arc CD = Arc TCD

Substituting the values given, We get,

⇒ 123° + Arc CD = 180° ( Reason :- Arc TCD is the diameter of circle )

Now, Transposing 123° to Right Hand Side, We get,

⇒ Arc CD = 180° - 123°

⇒ Arc CD = 57°

∴ Arc CD = 57°

Arc CD measures 57°

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

you est gay to much man grow some bollas also man kcuf off you little harry p u s s y. stupid