2) Multiply
(6x+3)(3x2+8x+5)
Help, please shore me how to do this!

Result :

3 • (2x + 1) • (x + 1) • (3x + 5)

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

STEP1

Equation at the end of step 1

(6x + 3) • ((3x2 + 8x) + 5)

STEP2

STEP3

Pulling out like terms

3.1 Pull out like factors :

6x + 3 = 3 • (2x + 1)

Trying to factor by splitting the middle term

3.2 Factoring 3x2 + 8x + 5

The first term is, 3x2 its coefficient is 3 .

The middle term is, +8x its coefficient is 8 .

The last term, "the constant", is +5

Step-1 : Multiply the coefficient of the first term by the constant 3 • 5 = 15

Step-2 : Find two factors of 15 whose sum equals the coefficient of the middle term, which is 8 .

-15 + -1 = -16

-5 + -3 = -8

-3 + -5 = -8

-1 + -15 = -16

1 + 15 = 16

3 + 5 = 8 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 5

3x2 + 3x + 5x + 5

Step-4 : Add up the first 2 terms, pulling out like factors :

3x • (x+1)

Add up the last 2 terms, pulling out common factors :

5 • (x+1)

Step-5 : Add up the four terms of step 4 :

(3x+5) • (x+1)

Which is the desired factorization

sorry if its too much...

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length