4b^2 +8b + 7 = 4

show your work I already have the answer!!

(-.5,0) and (-1.5,0)

or b= -.5

and b= -1.5

Step-by-step explanation:

First we want one side of the equation to equal 0

we have

4b²+8b+3=0

using the quadratic formula we have

(-b±√(b²-4*a*c))/2a

(-8±√(8²-4*4*3))/2*4

(-8±√(16))/8

(-8±4)/8

now we evaulate when ± is addition

(-8+4)/8

-4/8

-.5

and evaulate once more when the ± is subtraction

(-8-4)/8

-12/8

-1.5

Therefore the two solutions are (-.5,0) and (-1.5,0)

Step-by-step explanation:

step one - Move terms to the left side

(4b^2 + 8b + 7 = 4)

(4b^2 + 8b + 7 - 4 = 0)

step dose - Subtract the numbers

(4b^2 + 8b + 3 = 0)

step три - Use the sum-product pattern

(4b^2 + 6b + 2b + 3 = 0)

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above