If the specific heat of alu- minimum is 900 j/kg x c, how much energy is needed to raise the temperature of a 3 kg sample from 35c to 45c?

27000 J

Step-by-step explanation:

The specific heat equation is: Q = mC∆T

Q is the energy in Joules.

m is the mass in grams of the substance.

C is the specific heat capacity.

∆T is the change in temperature.

Let's plug in what we know.

The specific heat of aluminum is 900 j/kg ºCLet's convert j/kg to j/g by dividing by 1000.The specific heat capacity is 0.9 j/gºCWe have 3 kg of aluminum.Let's convert kg to g by multiplying by 1000.We have 3000 g of aluminum.The temperature is being raised from 35ºC to 45ºC, which is 10ºC

Q = 3000(0.9)(10)

Q = 27000 J

Hope this helps!

Logical equivalent of the give question is its contrapositive