There are 18 football teams in a league. each team plays two match against each of the teams work out the total number of matches played

34 matches

Step-by-step explanation:

Given

Total football team  = 18footbal teams

This  means that each team will play 17 other teams. This is equivalent to 17matches for each team in the first match round.

This can be expressed as;

17matches = 1 round

To get the total number of matches played if each team plays two match against each of the team, then;

x matches = 2rounds

Divide both expression

17/x = 1/2

Cross multiply

x * 1 = 17 * 2

x = 34

Hence the total number of matches played is 34 matches

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.