The histogram displays different numbers of days that customers rented a car. Which interval represents the most common number of days customers rented a car

See Explanation

Step-by-step explanation:

The question is incomplete, as the histogram is not attached.

However, the solution to your question is to select the interval with the highest frequency

Take for instance, after getting readings from the histogram, yiu have:

1 - 10: 8

11 - 20: 5

21 - 30: 11

31 - 40: 2

And so on

Interval 11 - 20 will represent the required interval because it has the highest frequency.

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.