Solve for p.
2p + 1=1
5p + 6=7

0 & 1/5

Step-by-step explanation:

If there are more questions in image I can't see that. I am answering on the basis of typed question .

We need to solve out and find out the value of p . The given equations are.

Question 1 :-

=> 2p + 1 = 1

=> 2p = 1 - 1

=> 2p = 0

=> p = 0/2

=> p = 0

Question 2 :-

=> 5p + 6 = 7

=> 5p = 7 - 6

=> 5p = 1

=> p = 1/5

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

mathpapa

step-by-step explanation: