This question is designed to be answered without a calculator. If dy/dx = 2x - (2^x) (ln2), what is the particular solution given that y = –2 when x = 0?

y = x² – 2^x
y = x² – 2^x – 1
y = x² – (2^x)(ln 2)
y = x² – ((2^x) – 1)(ln 2) – 2

im a goose

step-by-step explanation:

gg5

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

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step-by-step explanation: