Mathematics, 13.05.2021 01:00 dozsyerra

This question is designed to be answered without a calculator. If dy/dx = 2x - (2^x) (ln2), what is the particular solution given that y = –2 when x = 0?

y = x² – 2^x
y = x² – 2^x – 1
y = x² – (2^x)(ln 2)
y = x² – ((2^x) – 1)(ln 2) – 2

Answers: 2

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This question is designed to be answered without a calculator. If dy/dx = 2x - (2^x) (ln2), what is the particular solution given that y = –2 when x = 0? y = x² – 2^x y = x² – 2^x – 1 y = x² – (2^x)(ln 2) y = x² – ((2^x) – 1)(ln 2) – 2

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This question is designed to be answered without a calculator. If dy/dx = 2x - (2^x) (ln2), what is the particular solution given that y = –2 when x = 0?

y = x² – 2^x
y = x² – 2^x – 1
y = x² – (2^x)(ln 2)
y = x² – ((2^x) – 1)(ln 2) – 2