A line segment with endpoints A = (3, 0) and B = (7,0). Then, plot all points C = (x, y) such that the triangle ABC has an area of 12 square units.
What geometric formula and theorem are needed to solve this problem?

C(0,6)

Step-by-step explanation:

1) find the length of the base of the triangle

AB = 7-3 = 4

2) find the the height of the triangle

A = (base x height)/2

A x 2 = base x height

height = (A x 2)/base

height = (12 x 2)/4 = 6

3) find the equation of the line that passes threw the points AB

the two points have the same y so the equation of the line is

y = 0

4) use the formula of the distance between a point and a line to find C

|ax+by+c|/√a^2 + b^2 = distance

x = 0  

y = 6

C (0,6)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!