URGENT!! The length of a rectangle is five more than double the width. Find the dimensions if the
perimeter is 88m.

13, 31

Step-by-step explanation:

Set the width as x.

Length: 2x + 5

Perimeter:

(x) + (2x + 5) + (x) + (2x + 5) = 88

Simplify.

6x + 10 = 88

Solve.

6x = 78

x = 13

Substitute this into the previous equations

Width: 13

Length: 31

The length is 31m and the width is 13m.

Step-by-step explanation:

Start by translating the word problem into an equation. 5 more than double the width is written as 2w + 5. Then substitute that into the equation for the perimeter. It should look something like this:

88 = 2(2w +5) + 2w

Then simplify by combining like terms and solve for the width (w).

88 = 6w + 10

78 = 6w

13 = w

Now that we have the width, we can plug it back into the equation we made for the length.

l = 2w + 5

l = 2(13) + 5

l = 26 + 5

l = 31

I hope this could help!

a function could be identified in 3 ways either on a chart,graph, or ordered pairs. first a function is that each point has its own. the rule is that there can be many x's to one y but there can not be 2 x's at different y's. so on a graph when you put a straight line through the y's there should be one dot only to be a function.

step-by-step explanation:

the line of