1)factorize X^-3x-10
2) factorize 2x^+6x

1.Given:

x

2

−

3

x

−

10

Find a pair of factors of

10

which differ by

3

.

The pair

5

,

2

works in that

5

⋅

2

=

10

and

5

−

2

=

3

Hence we find:

x

2

−

3

x

−

10

=

(

x

−

5

)

(

x

+

2

)

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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