Please I need help and it has two answers for each one

1st Q: 3rd option, 2nd Q: 2nd, 4th, and 5th options

Step-by-step explanation:

For the first one, since the coefficient of the 2nd degree term is negative, the graph of the parabola will look downward, f(x) getting closer to infinity as the absoloute value of x gets larger.

For the second one, let f(x)=0 and solve the quadratic function with factoring. The equation can be rewritten as (x-12)(x+6)=0, so the roots are 12 and -6, which are x-intercepts. The y-intercept is the constant term of quadratic functions, so -36 is the y-intercept.

Solution given:

for second

we have

f(x)=x²-9x-36

let

y=x²-9x-36

when

x=0

y=-36

when

y=0

0=x²-9x-36

x²-12x+3x-36=0

x(x-12)+3(x-12)=0

(x-12)(x+3)=0

either

x=12

x=-3

So,

x and y intercepts are (-3,0)(12,0) and 0,-36)