What is the midpoint of the line with endpoints (3,-2) and (-3,6)

(0, 2)

Step-by-step explanation:

The coordinates of the midpoint of a line segment is given by

[(x2 + x1)/2 , (y2 + y1)/2]

Let P1 = (3, -2) and P2 = (-3, 6)

x-coordinate:

(1/2)(x2 + x1) = (1/2)[(-3) + 3] = 0

y-coordinate:

(1/2)(y2 + y1) = (1/2)[6 + (-2)] = 2

Therefore, the coordinates of the midpoint whose endpoints are (3, -2) and (-3, 6) are

(0, 2)

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

answer: $201

step-by-step explanation: to get the answer, you first get 3 nieces that he sold and multiply it by 67 and get $201, so he earned $201 selling his nieces.