A trebuchet launches a projectile on a parabolic arc from a height of 47 ft. at a velocity of 40 ft/s. Determine when the projectile will first reach a height of 60 ft. and how many seconds later it will again be at 60 feet. Round to the nearest tenth. First time to reach a height of 60 feet:
seconds

Second time to reach a height of 60 feet:
seconds

4th option is correct xy=-10

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step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice