Given that sinФ = 8/17 and cos Ф < 0: In which quadrant does the terminal side lie when it is placed in standard position?

What is the value of CosФ? CosФ =

What is the value of tanФ? TanФ =

1) The terminal side lies in quadrant 2

2) cosФ = -15/17

3) tanФ = -8/15

Step-by-step explanation:

1) First, we should realize that since sinФ = 8/17, it is positive. Thus, Ф must be in quadrants 1 or 2. And since cosФ is negative, Ф must be in quadrant 2 because cos, sin, and tan are all positive in quadrant 1

2) Next, we must realize that the sides given are a 8-15-17 right triangle. And in this case, since sinФ = 8/17, cosФ should be 15/17. But since cosФ is negative, cosФ = -15/17

3) Lastly, tanФ is opposite/adjacent. Since opposite of Ф is 8 and adjacent of Ф is 15, then tanФ should be 8/15, but since Ф is in quadrant 2, then tanФ is -8/15

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)