A birthday gift is placed inside a box with the height of 14 inches a length of 10 inches and a width of 7 inches. What is the minimum amount of wrapping paper needed
to wrap this gift?

The total surface area of the box would be the minimum amount of wrapping paper to wrap the gift.

The box is a cuboid, as it has 6 faces, 12 edges and a different height, breadth and length.

The total surface area of a cuboid is obtained by the formula 2(lb + lh + bh) where l stands for the length of the cuboid, b stands for it's breadth (also known as width), and h stands for it's height.

Total surface area = 2(lb + lh +bh)

                              = 2 (10*14 + 14*7 + 10*7)

                              = 2 (140 + 98 + 70)

                              = 2 x 308

                              = 616 square centimeters

Thus, the minimum amount of wrapping paper needed is 616 square centimeters.

Step-by-step explanation:

answer: $420.00

step-by-step explanation:   multiply $400.00 by 5%.

400.00*.05=20

400+20 = 420

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step-by-step explanation: