I need help on this angles on a straight line problem, it involves algebra. I don't need an explanation just the answer please.

m<COD = 46°

Step-by-step explanation:

All the angles are supplementary to each other, so we can combine them and set them equal to 180° to solve for x:

(3x+88)°+(x+36)°+(2x-4)°=180°

3x+88+x+36+2x-4=180

6x+120=180

6x=60

x=10

Since we know x=10, then <COD is 10+36 = 46°

∠COD = 46°

Step-by-step explanation:

∠AOB (or straight line) = 180°

3x + 88° + x + 36° + 2x - 4° = 180°

combine like terms:

6x + 120° = 180°

subtract 120° from both sides of the equation:

6x = 60°

divide both sides by 6:

x = 10°

∠COD = 10° + 36° = 46°

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