Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6 3/4 inches, and Frame B has a length of 7 1/2 inches.

WITHOUT CALCULATING, predict whicb frame has the SHORTER WIDTH. Explain you reasoning.

Pleaseee HELP!! Pls support your answer by reasoning

Question:

Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6 3/4 inches, and Frame B has a length of 7 1/2 inches.

 1. the longer frame (B) has the shorter width

 2. the shorter width is 6 3/7 inches, area divided by length

Step-by-step explanation:

The relation between area, length, and width is ...

 A = LW

Then the width is ...

 W = A/L . . . . .  inversely proportional to length

1. Since length and width are inversely proportional (when area is constant), the shorter width will be associated with the longer length. Frame B will have the shorter width.__

2. The width of frame B is ...

 W = A/L = (45 in²)/(7 in) = 45/7 in = 6 3/7 in

-Alan Becker

i dont know

step-by-step explanation: