What two numbers equal 6 when multiplied but equal —7 when added?

6 and 1

Step-by-step explanation:

-1 , -6

Step-by-step explanation:

Let x be the first number and let y be the second number.

x * y = 6

x + y = -7

Let's first find the factor pairs of 6.

1, 6

2, 3

-1, -6

-2, -3

Now, we just need to take each factor pair and add them together and see which one equals -7.

1 + 6 = 7, so that is wrong.

2 + 3 - 5, so that is also wrong.

-1 - 6 = -7, so this is our answer (-2 and -3 added is -5, which is wrong).

Therefore, our answer is -6 and -1.

vertical=18cm horizontal=18cm hypotenuse=25.5

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.