Based on statistics for the past several seasons, the probability that the best player on a basketball team makes a free throw is 8/10. the probability that the second-best player makes a free throw is 13/20. if both players attempt 140 free throws over a season, how many more free throws is the best player expected to make? Please help!!!

The best player is expected to make  

21 more free​ throw(s).

Step-by-step explanation:

1) Make a proportion

2) Find the unknowns

3) Subtract the greater number from the smaller one

4) That's it.

He is expected to make 21 more free throws

Step-by-step explanation:

we know that the probability for the best player is 8/10 or 80%

the probability for the second best is 13/20. This is equivalent to 65%

They each attempt 140 free throws.

We need to figure out what 80% of 140 is. To do this, we need to multiply 140 by 0.80. 140 * 0.80 = 112

We do the same for the second best

140 * 0.65 = 91

112 - 91 = 21.

Hope this helped

step-by-step explanation:

i am not sure sorry : c

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb