PLEASE Hurry If f(x)=7x2−2 and g(x)=2(x−7)2 , which is an equivalent form of f(x)−g(x) ? A 5x2−100 B 5x2+28x−100 C 5x2+14x−51 D 3x2+56x−198

Step-by-step explanation:

PLEASE Hurry If f(x)=7x2−2 and g(x)=2(x−7)2 , which is an equivalent form of f(x)−g(x) ? A 5x2−100 B 5x2+28x−100 C 5x2+14x−51 D 3x2+56x−198

5x^2 +28x - 100

Step-by-step explanation:

f(x)=7x^2−2 and g(x)=2(x−7)^2

First simplify g(x)

g(x) = 2 ( x-7)(x-7) = 2( x^2 - 7x -7x +49) = 2(x^2 -14x +49) = 2x^2 -28x +98

Now f(x) - g(x)

f(x) - g(x) = 7x^2−2 - (2x^2 -28x +98)

Distribute the minus sign

            = 7x^2−2 - 2x^2 +28x -98

Combine like terms

            = 5x^2 +28x - 100

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐