Rick wants to use multiplication to solve {k} = 7 \div \dfrac13k=7÷ 3 1 ​ k, equals, 7, divided by, start fraction, 1, divided by, 3, end fraction. Which multiplication equation can Rick use? Choose 1 Choose 1 (Choice A) A \dfrac13\times{k} =7 3 1 ​ ×k=7start fraction, 1, divided by, 3, end fraction, times, k, equals, 7 (Choice B) B \dfrac13={k}\times7 3 1 ​ =k×7start fraction, 1, divided by, 3, end fraction, equals, k, times, 7 (Choice C) C \dfrac13\times7 = {k} 3 1 ​ ×7=kstart fraction, 1, divided by, 3, end fraction, times, 7, equals, k

(a)

Step-by-step explanation:

Given

Equation is

Write the cross-multiplication of the given equation i.e.

This corresponds to the option (a).

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation:

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column