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Mathematics, 10.05.2021 18:40 robert7248

___cosb=1/2[cos(a+b)+cos(a-b)]
A. Sinb
B. Sina
C. Cosb
D. Cosa


___cosb=1/2[cos(a+b)+cos(a-b)]
A. Sinb 
B. Sina 
C. Cosb
D. Cosa

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Answers: 2

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You know the right answer?
___cosb=1/2[cos(a+b)+cos(a-b)]
A. Sinb
B. Sina
C. Cosb
D. Cosa
...

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