Help for easy points

58 units²

Step-by-step explanation:

Using Pythagoras identity

The square on the hypotenuse ( third side ) is equal to the sum of the squares on the other 2 sides, then

area = 7² + 3² = 49 + 9 = 58

Step-by-step explanation:

Firstly: using pythagoras theorem

Hyp^2=adj^2+opp^2

Let the hyp be x

X^2=7^2+3^2

X^2=49+9

X^2=58

X=Square root 58

Let the side is root 58

Area of a square is L^2

Root 58×root 58

The area of the square is 58unit squ

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