Part 1: Use the Pythagorean Theorem to find the length of the missing side in each triangle below Part 2: Use the Pythagorean Theorem to determine whether the triangles below are right triangles. (c is the longest side)
will give brainliest

down there with the work :)

Step-by-step explanation:

formula: a^2+b^2=c^2

Page 1:

1)

6^2+8^2=c^2

36+64=c^2

100=c^2

take the square root of both sides

c=10

2)

8^2+b^2=12^2

64+b^2=144

80=b^2

b=

3)

14^2+b^2=48^2

196+b^2=2304

b^2=2108

b=

Page 2:

1)

5^2+11^2=13^2

25+121=169

no this is not true so this is not a right triangle

2)

10^2+24^2=26^2

100+576=676

this is true so this IS a right triangle

hope this helps!

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?