Make up an equation of the form y = kx +b, the graph of which passes through the following points: P (4, 1) and Q (3, –5)

y=6x-23

Step-by-step explanation:

Step-by-step explanation:

m = (y2 - y1)/(x2-x1)

m = (-5 -1)/(3-4) = -6/-1 = 6

y = 6x + b

then

slope point form

y - y1 = m (x - x1)

y - 1 = 6 (x - 4)

y - 1 = 6x - 24

y = 6x - 23

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.