A pressure of 1200 lbs per it is exerted by 3 i gas in a cylinder. If a piston pushes into the
cylinder until the volume is 2 ft", what will be tt
pressure exerted by the gas?

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8

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step-by-step explanation:

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did you get the answer yet?

step-by-step explanation: