Find the constant a, P and Q such
that 3x²-12x+16=a(x+p) +q​

Step-by-step explanation:

Rewrite 3x²-12x+16 as follows:

3(x^2 - 4x) + 16

Complete the square of x^2 - 4x; it is (x - 2)^2 - 4.  We then have:

3( (x - 2)^2 - 4) + 16, or:

3(x - 2)^2 - 12 + 16, or

3(x - 2)^2 + 4

Then a = 3, p = -2 and q = 4

Completing the square of x^2 - 4x is done as follows:

1.  Identify the coefficient of x:  It is -4.

2.  Take half of this result:  It is -2

3.  Square this, and then add the square to x^2 - 4x, and then subtract it:

    x^2 - 4x = x^2 - 4x + 4 - 4

4.  Rewrite this result in the form (x - a)^2 - c:

    (x - 2)^2 - 4  

5.  Now follow the remainder of the problem solution (given above)

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation: