Find the equation of the line that passes through (1,3) and is perpendicular to y=1−2x. Leave your answer in the form y=mx+c

The equation of the line  that passes through (1,3) and is perpendicular to y=1−2x is y=1/2x+5/2

Step-by-step explanation:

We can rewrite the original equation as y=-2x+1

To find an equation's perpendicular slope, you take the reciprocal of it and negate it, therefore the perpendicular slope is -2 -> 1/-2 -> 1/2

So far, we have y=1/2x+b, but to find the y-intercept, b, we would need to plug in (1,3) and solve for b:

y=1/2x+b

3=1/2(1)+b

3=1/2+b

5/2=b

Therefore, your final equation is y=1/2x+5/2

i think it is c, not positive though

step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c