A kite has a string tied to its center. The kite is let out on 90 ft of the string and the other end of the string is held at 4 ft above the ground. From where the string is held, the angle of elevation to the center of the kite is 40°. If you maintain the same angle of elevation from where the string is held, how much more string would you need to let out for the kite to fly 10 ft higher? Round to the nearest tenth of a foot. A. 15.6
B. 11.9
C. 15.9
D. 19.6

45

step-by-step explanation:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.