Describe the graph of a function g by observing the graph of the base function ƒ. A) g(x)= f (½x)+1
B) g(x) = 2ƒ(x) – 1C)
C) g(x) = 2ƒ(x + 1)
D)g(x) = 2ƒ(2x) + 1

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

5: 20

step-by-step explanation: