A magazine cover measures 28 cm by 22 cm. The title uses one-quarter of the area of
the cover. How much area is needed for the
title?

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

sine

step-by-step explanation:

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