An arrow is shot straight up with an initial velocity of 50 m/s. (a) Find the time to reach the highest point. (b) How high does the arrow go? (c) Find the arrow's height when the velocity is 25 m/s.

sorry man i accidentally pressed yes my bad

step-by-step explanation:

no

step-by-step explanation:

27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a