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Mathematics, 06.05.2021 19:10 unicornqueen30
A jawbreaker candy machine has 25 red jawbreakers, 30 green jawbreakers, 15 yellow jawbreakers, and 20 blue jawbreakers. If Loretta puts 1 coin in the machine and gets 1 jawbreaker, what is the probability the jawbreaker is NOT green?
A. 2/5
B. 1/3
C. 2/3
D. 1/60
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Answers: 3
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Mathematics, 22.06.2019 01:10, hellicuh
Evaluate 8x2 + 9x − 1 2x3 + 3x2 − 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 − 2x = x(2x2 + 3x − 2) = x(2x − 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the form† 8x2 + 9x − 1 x(2x − 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x − 1)(x + 2), obtaining 8x2 + 9x − 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x − 1).
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A jawbreaker candy machine has 25 red jawbreakers, 30 green jawbreakers, 15 yellow jawbreakers, and...
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