A jar contains q quarters and d dimes. There are 7 coins in the jar and the total value of the coins is $1.00. Which system of equations can be used to find how many of each type of coin is in the jar? A.0.25q + 0.10d = 1.00
q + d = 7

B.0.10q + 0.25d = 1.00
q + d = 7

C.25q + 10d = 1
q + d = 7

D.0.25q + 0.10d = 7.00
q + d = 1

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

cheater

step-by-step explanation:

inch

step-by-step explanation:

yard and mile are too big.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)