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Every year, the students at a school are given a musical aptitude test that rates them from 0 (no musical
aptitude) to 5 (high musical aptitude). This year's results were:
Aptitude Score
Frequency
0
6
1
3
2 3
23
4
6
5
3
The average (mean) aptitude score:
The median aptitude score:
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Question 8
5/5 pts 19
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answer: 38.47 is your answer

step-by-step explanation: hope i you and who ever sees this answer have a great rest of your day : )

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

d i think

step-by-step explanation: