Given vectors \mathbf{v} = ⎡⎣−4−38⎤⎦
v=
⎣
⎢
⎡
​

−4
−3
8
​

⎦
⎥
⎤
​
, \mathbf{b_1} =
⎡⎣123⎤⎦
b
1
​
=
⎣
⎢
⎡
​

1
2
3
​

⎦
⎥
⎤
​
, \mathbf{b_2} =
⎡⎣−210⎤⎦
b
2
​
=
⎣
⎢
⎡
​

−2
1
0
​

⎦
⎥
⎤
​
and \mathbf{b_3} =
⎡⎣−3−65⎤⎦
b
3
​
=
⎣
⎢
⎡
​

−3
−6
5
​

⎦
⎥
⎤
​
all written in the standard basis, what is \mathbf{v}v in the basis defined by \mathbf{b_1}b
1
​
, \mathbf{b_2}b
2
​
and \mathbf{b_3}b
3
​
? You are given that \mathbf{b_1}b
1
​
, \mathbf{b_2}b
2
​
and \mathbf{b_3}b
3
​
are all pairwise orthogonal to each other.

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116