The line y = kx + 6 is a tangent to the graph of f(x) = x^2 - 4x + 3

Find the possible values of k.​

Step-by-step explanation:

For equating the equations, you get

x2 + kx - 3x + 4 = 0               eq1

Setting the derivative of f(x) equal to 3 yields

f'(x) = 3

2x + k = 3                           eq2

Now we substitute the value of k from eq2 into eq1.

x2 + x(3 - 2x) - 3x + 4 = 0

Solve for x from this equation.  Then plug in the value of x into eq2 to solve for k

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step-by-step explanation:

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