In ΔBCD, \overline{BD} BD
is extended through point D to point E, \text{m}\angle BCD = (2x-1)^{\circ}m∠BCD=(2x−1)
∘
, \text{m}\angle CDE = (7x-19)^{\circ}m∠CDE=(7x−19)
∘
, and \text{m}\angle DBC = (x+10)^{\circ}m∠DBC=(x+10)
∘
. Find \text{m}\angle CDE. m∠CDE.

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At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.