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Mathematics, 05.05.2021 18:50 lolagrace06

the side of a wooden chest is a quadrilateral with AB parallel to CD and BC parallel to DA. If m
A. Both pairs of opposite sides are parallel so ABC E is a parallelogram. One income measuring 90° does not provide enough information to classify as anything more specific.
B. Both pairs of opposite sides are parallel so ABC D is a parallelogram. Since one angle measures 90°, we can determine that the others are also right angles. So this is more specifically a square.
C. Both pairs of opposite sides are parallel so ABCD is a rhombus. Since one angle measures 90°, we can determine that the others are also right angles. So this is more specifically a square.
D. Both pairs of opposite such a parallel so ABC D is a parallelogram. Since one angle measures 90°, we can determine that the others are also angles. So this is more specifically rectangle.


the side of a wooden chest is a quadrilateral with AB parallel to CD and BC parallel to DA. If m

A

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the side of a wooden chest is a quadrilateral with AB parallel to CD and BC parallel to DA. If m

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