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Mathematics, 05.05.2021 18:10 nene3210204

1. In the image shown, m_ABD = (3x + 15)° and mDBC = 2.c) ind mZDBC. mZDBC 60° O m2DBC= 20° O m_DBC 30° in/DBC 90°​


1. In the image shown, m_ABD = (3x + 15)° and mDBC = 2.c) ind mZDBC. mZDBC 60° O m2DBC= 20° O m_DBC

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1. In the image shown, m_ABD = (3x + 15)° and mDBC = 2.c) ind mZDBC. mZDBC 60° O m2DBC= 20° O m_DBC...

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