CC Geometry Honors Test 4.2 5/5/2021
1 point
Question: *
In AEKF, points G and Hare located on sides EK and FK such that GH is parallel to EF .Which mapping
of AGKH described below would justify that AGKH is similar to AEKF ?
E
(1) a dilation by a factor of
centered at K
10
3
(2) a dilation by a factor of centered at K
2
5
(3) a dilation by a factor of centered at G
3
u | نیا نیا یہ نیا نیا د
15
K
H
F
12
8
centered at G
(4) a dilation by a factor of
O (1)

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation:

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a