The Griswold Institute Exam is composed of a number of subtests. On one subtest, the scores have a mean of 56 and a standard deviation of 5. Assuming these scores form a normal distribution: PART 1: What score represents the 91st percentile?

PART 2: What is the probability of getting a score between 52 and 62?

it would be see explanation

Step-by-step explanation:

The n th term of a geometric sequence is

= a

where a is the first term and r the common ratio

Both a and r have to be found

Given a₃ = - 2, then

ar² = - 2 → (1)

Given a₇ = - 32, then

a = - 32 → (2)

Divide (2) by (1)

= , that is

= 16 ( take the fourth root of both sides )

r = 2 ← common ratio

Substitute r = 2 into (1)

a × 2² = - 2, that is

4a = - 2 ( divide both sides by 4 )

a = -  ← first term

. easy

Hence

= -  ← explicit formula

and

= -  ×  = - 0.5 × 512 = - 256

Step-by-step explanation:

answer:

idk

step-by-step explanation: