Mathematics, 05.05.2021 04:10 76022sfox

Do you have a bedtime?

Answers: 2

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Answers

Answer from: anthonybowie99

nope

Step-by-step explanation:

Answer from: kayla2945

i used to when I was younger

when i was 5 or 6 my bedtime was 9:30 pm

Now...since im older i don't have a bedtime

older kids generally don't have a bedtime

Answer from: Quest

2 & 7

step-by-step explanation:

he climbs 300 ft/hr at a constant rate. the peak is at 1,500 ft.

when going up, he reaches 600 ft in 2 hours. remember, that he is going in a constant rate. divide 600 with 300:

600/300 = 2

assuming that he takes the same route back (meaning that it's a 1500 ft route back, you can solve.

note also that you are solving when he gets back to 600 ft after he reaches the peak.

first, find the amount of hours it takes to get up the peak. divide the total amount (1500), with the ft/her (300) to get the amount of hours (x):

1500/300 = x

x = 5

it takes jamie 5 hours to get up. now, he is returning down, and reaches 600 (his current destination). remember that he climbs at a constant 300 ft/hr. divide 600 with 300:

600/300 = x

x = 2

now add the two numbers together.

x = 5 + 2 = 7

jamie takes 7 hours to go up the mountain and reach his current position when descending.

(total amount/constant rate) = (time).

remember that it is a constant rate, so in total, when he gets back down the mountain, it will take the same amount of time as when he goes up. the total amount for the round trip is: 5 + 5 = 10.

Answer from: Quest

answer: the correct option is d.

explanation:

it is given that the triangle j'k'l' shown on the grid below is a dilation of triangle jkl using the origin as the center of dilation.

from the given graph it is noticed that k(4,8) and k'(2,4). let origin is defined by o and scale factor is defined by k, then

$k=\frac{ok'}{ok}$ (1)

distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$ok'=\sqrt{(2-0)^2+(4-0)^2}= \sqrt{4+16}= \sqrt{20}=2\sqrt{5}$

$ok=\sqrt{(4-0)^2+(8-0)^2}= \sqrt{16+64}= \sqrt{80}=4\sqrt{5}$

put these values in equation (1).

$k=\frac{2\sqrt{5}}{4\sqrt{5}}= \frac{1}{2}$

therefore scale factor is $\frac{1}{2}$ and option d is correct.

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