PLEASE HURRY Kevin rides the bus to school each day. He always arrives
at his bus stop on time, but his bus is late 80% of the time.
Kevin runs a simulation to model this using a random
number generator. He assigns these digits to the possible
outcomes for each day of the week:
• Let 0 and 1 = bus is on time
• Let 2, 3, 4, 5, 6, 7, 8, and 9 = bus is late
The table shows the results of the simulation.
Group number 1
2
3
4
5
Random digits 28713 01792 00095 72765 24943
Group number 6
7
8
9
10
Random digits 39638 24697 | 47511
0929771197
What is the estimated probability that Kevin's bus will be late every day next
week?

for a it would be 24 children.

for b i don't understand the question. is it saying for each individual person they pick 5 reds to 7 greens or is it the whole group. clarify and i hope this can you.

step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

y=sec x is the correct answer

~batmans wife dun dun